Timeline for How does the energy remain conserved in a transformer?
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| Apr 13, 2017 at 12:33 | history | edited | CommunityBot |
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| Feb 23, 2016 at 18:23 | comment | added | Anindya Mahajan | @AlfredCentauri, Oh! So do you mean that this discrepancy arises from the fact that I considered only the resistance when I should have considered the impedance (which would have included both the resistance and inductive reactance of the coil)? | |
| Feb 21, 2016 at 14:10 | comment | added | Farcher | @AlfredCentauri Thank you for all you very helpful comments. | |
| Feb 21, 2016 at 13:23 | comment | added | Alfred Centauri | @AnindyaMahajan, Ohm's law doesn't apply to ideal inductors, ideal capacitors, ideal transformers etc. because they aren't ohmic devices. Another way to think of this is, for the ideal transformer, the winding resistance is zero so applying Ohm's law gives zero power dissipated (in the windings) for any finite current through. However, Ohm's law applies to, for example, the resistive load connected to the secondary. | |
| Feb 21, 2016 at 13:17 | comment | added | Alfred Centauri | @Farcher, an ideal transformer can be understood as two perfectly coupled ideal inductors in the limit as the inductances go to infinity (keeping the ratio of inductances constant). See, e.g., Ideal Transformer. So, for example, an ideal transformer transforms DC voltages and currents as well as arbitrarily high frequency voltages and currents without loss. The model in my answer clearly has a finite bandwidth as well as dissipative losses. But these do not come from the ideal transformer within in the model. | |
| Feb 21, 2016 at 8:45 | comment | added | Anindya Mahajan | so do you mean that ohm's law isn't applicable in the case of a transformer? | |
| Feb 21, 2016 at 7:56 | comment | added | Farcher | Thank you for you informative comment to my answer which I have removed but unfortunately that has removed your comment.I am interested in the characteristics of your ideal transformer other than being 100% efficient.I assume that adding a load resistor to the secondary will mean that the induced emf in the secondary circuit will induce a current in the load resistor?Does the source see the resistance of the load divided by the turns ratio squared?For analysis of real transformer that is what you replace the ideal transformer with on the primary side?Would it also be true for a reactive load? | |
| Feb 21, 2016 at 2:44 | history | edited | Alfred Centauri | CC BY-SA 3.0 |
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| Feb 21, 2016 at 0:48 | history | answered | Alfred Centauri | CC BY-SA 3.0 |