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Feb 23, 2018 at 14:32 comment added orion @cms That's always the case... induced voltage is proportional to magnetic field... current is proportional to voltage and force is proportional to the product of magnetic field and current, therefore proportional to the square of magnetic field. The shape and all the effects are in the factor in front, but B^2 is always there.
Feb 23, 2018 at 13:30 comment added cms Why was it assumed the force is proportional to the square of the magnetic field?
Apr 13, 2017 at 12:39 history edited CommunityBot
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Feb 19, 2016 at 17:49 comment added Shadow503 Also, most bullets have a thick copper jacket, which would have much lower resistivity than lead. A lot of surplus ammunition also has a steel core. Perhaps that number could be reduced even further in practice?
Feb 19, 2016 at 10:24 comment added orion Yes, perpendicular... see the geometry of the disk brakes in the links.
Feb 19, 2016 at 10:06 comment added Adithya Arya So .... the bullet needs to move perpendicular to the direction of the field ?
Feb 19, 2016 at 10:02 comment added user56903 You will also have to shoot the bullet so it crosses the field lines. Shooting it down the axis of an MRI imaging chamber (for example) would not do much
Feb 19, 2016 at 9:47 comment added orion Depends on the size of the bullet. A 9mm, probably yes. And keep in mind that the velocity over time is exponential, so the majority of energy is lost at the very beginning - "almost instantly" is quite a good description. You can calculate the characteristic time $\tau$ by yourself. However, the distance travelled will still be quite long.
Feb 19, 2016 at 9:46 comment added Adithya Arya not slow down but almost instantly stop the bullet
Feb 19, 2016 at 9:41 comment added Adithya Arya So taking into consideration the circumstances, can a field of say 2T stop the bullet entirely..??
Feb 19, 2016 at 9:01 history answered orion CC BY-SA 3.0