Timeline for Compton effect in photo-electric?
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Feb 7, 2016 at 17:55 | comment | added | aquirdturtle | Let us continue this discussion in chat. | |
| Feb 7, 2016 at 11:37 | comment | added | anna v | @aquirdturtle we are talking at cross purposes. The compton effect, I have given a link in my answer, is about scattering of a photon off an electron, and might be extended to scattering of a photon off a field , where the generator of the field takes up the momentum balance. The spectrum is continuous. The photoelectric effect gives a lower bound to the rebounding momentum of the electron, and this implies bound states with a specific ionization energy , I also gave a link in the answer. If the electrons on the metal surface were not quantum mechanically bound, there would be no cut off. | |
| Feb 7, 2016 at 11:32 | history | edited | anna v | CC BY-SA 3.0 |
clarification
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| Feb 7, 2016 at 10:54 | comment | added | aquirdturtle | I'm referring to your statement "Compton scattering occurs on free electrons, i.e. not in a bound state." And the link you gave when saying "If the particle it scatters off is bound, one needs a photon with the ionization energy, which means quantized steps and the photon is absorbed in the process" clearly refers to the Compton effect. | |
| Feb 7, 2016 at 10:53 | comment | added | anna v | @aquirdturtle my comment addresses the photoeletric effect, which is not compton scattering. Of course photons can scatter off the field of atoms, that is not what the question is about, imo | |
| Feb 7, 2016 at 10:49 | comment | added | aquirdturtle | that's not true. The photon needs not have the ionization energy and it needs not be absorbed in the process. Your comment seems to imply that photons that aren't resonant with specific transitions can't scatter off of or interact with atoms. Your link definitely refers to the bound case, but that doesn't mean there aren't other cases involving bound particles which involve the same phenomena. | |
| Feb 7, 2016 at 10:46 | comment | added | anna v | @aquirdturtle If the particle it scatters off is bound, one needs a photon with the ionization energy, which means quantized steps and the photon is absorbed in the process. It is a specific feynman diagram. see the link | |
| Feb 7, 2016 at 9:38 | comment | added | aquirdturtle | I don't think "Compton Scattering" necessarily has to be off of free particles or electrons specificially. It's just an effect seen in the scattering off of charged particles. I think that it's just usually treated in the special case of a free particle as an easy simplification. | |
| Feb 7, 2016 at 6:43 | history | answered | anna v | CC BY-SA 3.0 |