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Apr 6, 2012 at 12:44 comment added Ron Maimon @LubošMotl: yes, of course, stupid, stupid (r=M for RN). What the heck? No third law. This must be what Kaanen did, found condensed matter analogs of the glassy BH states. This is interesting. +1,nice answer.
Apr 6, 2012 at 7:39 comment added Luboš Motl Dear Ron, SUSY is by no means necessary for a nonzero horizon area of extremal black holes. Ordinary extremal Kerr and Reissner-Nordstrom black holes in $d=4$ (without SUSY) have $T=0$ but a nonzero area as well, don't they? What was needed for just some extra charge(s) and/or angular momentum. SUSY is helpful to cancel corrections and make many calculations more doable (Strominger-Vafa brane was the minimal, highest-SUSY one with a nonzero horizon area) but it doesn't "qualitatively" change the physical behavior of the systems.
Apr 6, 2012 at 6:49 comment added Ron Maimon Hi Lubos: the Strominger-Vafa system already has nonzero horizon area at zero temperature, but I assumed that such degeneracies were due to highly supersymmetric nature of these states. If you have a crystal with degeneracies in the ground state, you don't have SUSY (I guess), so how do you get ground state entropy? I also thought there are other cases where you have a glassy ground state where you could have a highly degenerate ground state in principle, but I can't think of a quantum one off the top of my head.
Apr 6, 2012 at 5:46 history answered Luboš Motl CC BY-SA 3.0