Timeline for How can I solve this quantum mechanical "paradox"?
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Jan 28, 2022 at 1:43 | history | edited | Níckolas Alves | CC BY-SA 4.0 |
Fixed typo
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| Feb 5, 2016 at 11:43 | vote | accept | user32109 | ||
| Feb 3, 2016 at 15:40 | comment | added | Andrea | @ACuriousMind You answer is detailed and very informative. However, it seems to me to miss OP's question's spirit, which is about the HUP understood colloquially as the product of the uncertainty about the position and momentum of a particle is always larger than some non-zero bound. To better you answer you could perhaps consider adding a less mathematical punch-line. | |
| Feb 3, 2016 at 14:18 | comment | added | ACuriousMind♦ | @AndreaDiBiagio: It is the last equation in my post. For plane waves, the r.h.s. reads zero, so $\sigma_p = 0$ is not a contradiction. For functions in $D([x,p])$, it is the usual $\sigma_p\sigma_x\geq\hbar/2$. I'm not sure what you think there needs to be recovered. | |
| Feb 3, 2016 at 8:53 | comment | added | Andrea | But how do you recover Heisenberg's uncertainty principle then? | |
| Feb 2, 2016 at 15:42 | history | edited | ACuriousMind♦ | CC BY-SA 3.0 |
removed discussion of a different operator
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| Feb 2, 2016 at 14:57 | history | answered | ACuriousMind♦ | CC BY-SA 3.0 |