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Post Closed as "Duplicate" by John Rennie thermodynamics
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Brionius
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My textbook says that net rate of heat transfer due to radiation is εσA(T^4-To^4)$\epsilon \sigma A(T^4-T_o^4)$ but i couldn't understand it.

Rate of emission is εσAT^4$\epsilon \sigma A T^4$ and rate of absorption is aσATo^4$a \sigma A T_o^4$ so net rate of heat transfer must be εσAT^4-aσATo^4$\epsilon \sigma A T^4 - a \sigma A T_o^4$,it is possible only if a=e$a=e$ which means body is in thermal equilbriumequilibrium.

But that is not always the case.please Please help.

My textbook says that net rate of heat transfer due to radiation is εσA(T^4-To^4) but i couldn't understand it.

Rate of emission is εσAT^4 and rate of absorption is aσATo^4 so net rate of heat transfer must be εσAT^4-aσATo^4,it is possible only if a=e which means body is in thermal equilbrium.

But that is not always the case.please help

My textbook says that net rate of heat transfer due to radiation is $\epsilon \sigma A(T^4-T_o^4)$ but i couldn't understand it.

Rate of emission is $\epsilon \sigma A T^4$ and rate of absorption is $a \sigma A T_o^4$ so net rate of heat transfer must be $\epsilon \sigma A T^4 - a \sigma A T_o^4$,it is possible only if $a=e$ which means body is in thermal equilibrium.

But that is not always the case. Please help.

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Please help me with this doubt from thermodynamics

My textbook says that net rate of heat transfer due to radiation is εσA(T^4-To^4) but i couldn't understand it.

Rate of emission is εσAT^4 and rate of absorption is aσATo^4 so net rate of heat transfer must be εσAT^4-aσATo^4,it is possible only if a=e which means body is in thermal equilbrium.

But that is not always the case.please help