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Dec 30, 2010 at 16:06 vote accept Jeremy
Dec 29, 2010 at 15:56 comment added Graviton why you are asking and answering the same question at the same time?
Dec 28, 2010 at 16:27 comment added Jeremy That is what I thought too. I'm no expert, but from looking around the web, it seems the $v^2$ scaling is pretty universal, even for supersonic flight. But the drag coefficient may change, as "wave drag" becomes important around the sound barrier. In hypersonic flight, the problem actually reverts to a simpler one, where the air molecules are treated as elastic scattering events, which explains the $\rho v^2$ scaling.
Dec 28, 2010 at 16:04 comment added unsym Is the drag force is still the same when the bullet speed is much higher than the sound speed?
Dec 28, 2010 at 16:01 comment added dmckee --- ex-moderator kitten I doubt that a $v^2$ dependence is the whole story for objects with speeds on order of km/s. It is certainly not the whole story for objects at or above Mach 1, which means that achieving those kinds of velocities in the lower atmosphere renders these kinds of estimates very rough indeed.
Dec 28, 2010 at 15:54 history edited Jeremy CC BY-SA 2.5
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Dec 28, 2010 at 15:33 history answered Jeremy CC BY-SA 2.5