Timeline for Fayet-Iliopoulos terms
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 24, 2016 at 9:18 | comment | added | Axion | @JohnDoe Isn't the full gauge symmetry is simply given by $V\rightarrow V+i(\Phi-\bar{\Phi})$ under which the FI term in superspace is invariant? | |
| Jan 22, 2016 at 17:23 | comment | added | John Doe | How can FI term be invariant under the full gauge symmetry? FI term is $D$, just $D$, which is the last component of a vector multiplet. $S_{FI} = \xi \int d^4 x D$. How can you generalize this to YM? The way you obtain this action is that you take a real multiplet, and consider it's highest component $D$ as an action. Then you impose WZ condition. This takes four components of the real multiplet including the auxiliary vector and the auxiliary scalar $D$, and turns it into a vector multiplet which is determined by $G = U(1)$. Thus you get FI terms, which is the highest component of vec. mult. | |
| Jan 22, 2016 at 17:10 | comment | added | user46925 | @Axion from where comes the exact form of the F terms you used ? from which model precisely ( and book ) ? | |
| Jan 22, 2016 at 13:26 | comment | added | Axion | I understand that the supercurrent is gauge invariant only under the WZ gauge but the above FI term in superspace is invariant under the full gauge symmetry. Can't see the WZ restriction in superspace. | |
| Jan 22, 2016 at 9:56 | comment | added | user46925 | it was to answer the last question ... But you said the main thing to the OP | |
| Jan 22, 2016 at 6:10 | comment | added | John Doe | yes, but also this is well known that adding FI restricts YM theory to $G = U(1)$. | |
| Jan 22, 2016 at 1:31 | comment | added | user46925 | well seen ... don't you cite the 2nd paragraph of the introduction from the 3rd sentence ? | |
| Jan 21, 2016 at 22:18 | history | edited | John Doe | CC BY-SA 3.0 |
deleted 531 characters in body
|
| Jan 21, 2016 at 22:05 | history | answered | John Doe | CC BY-SA 3.0 |