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May 2, 2020 at 9:43 comment added Alex Zeffertt It was a mistake. I've just checked and he issued an errata doc!
May 2, 2020 at 9:38 comment added Alex Zeffertt Hi Bass. Are you reading Student Friendly Quantum Field Theory by Klauber? On page 256 he says the Dyson term " $S^{(3)}$ plays no role in QED and can be ignored". I couldn't see why either and was confused. Having read the answers to your question I wonder if this is just a mistake in the book.
S Jan 3, 2018 at 0:10 history bounty ended knzhou
S Jan 3, 2018 at 0:10 history notice removed knzhou
Jan 2, 2018 at 23:04 answer added Cosmas Zachos timeline score: 6
S Dec 29, 2017 at 1:08 history bounty started knzhou
S Dec 29, 2017 at 1:08 history notice added knzhou Draw attention
Sep 15, 2017 at 22:30 history tweeted twitter.com/StackPhysics/status/908820463551483904
Sep 15, 2017 at 16:07 comment added user154997 Your s-channel diagram and all the others where the photon is emitted from another leg, as well as all the t-channel diagrams definitively have a non-zero contribution. $e^+e^-\to e^+e^-\gamma$ was quite important to know at LEP (including a $Z^0$ exchange as well a photon), and a great deal of work has been poured into computing the cross-sections. The classic reference is Anthony C. Hearn, P. K. Kuo, and D. R. Yennie. Radiative corrections to an electron-positron scattering experiment. Phys. Rev., 187:1950–1963, Nov 1969.
Jan 18, 2016 at 14:44 comment added Bass @ACuriousMind In the lecture notes I'm reading, the professor explained that third-order terms vanish (most likely in the sense of "vanish as a sum because of interference"), and he went on to describe some examples of third-order terms that vanish because of off-shell real particles. Let's wait and see, maybe someone knows it for certain. Thanks.
Jan 18, 2016 at 14:32 comment added OON @ACuriousMind Yeah, that's true. I would still look at its sum with a similar diagram for the same process with not electron but positron radiating.
Jan 18, 2016 at 14:16 comment added ACuriousMind Bass, why do you think this diagram should vanish? It just looks like an $e^+ +e ^-\to e^+ + e^-$ concatenated with a bremsstrahlung diagram, and neither of those vanish. That the third-order contributions in total vanish doesn't mean the individual diagrams vanish - it might just destructively interfere with another third-order diagram.
Jan 18, 2016 at 14:14 comment added ACuriousMind @OON: Furry's theorem is usually stated as "diagrams with a fermion loop and an odd number of external photon legs vanish". It's not immediate to see how to apply it to this diagram.
Jan 18, 2016 at 13:59 comment added OON Do you remember Furry theorem? Note that it works only for the sum of the diagrams not for individual ones.
Jan 18, 2016 at 13:45 history asked Bass CC BY-SA 3.0