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If $v$ is the true anomalytrue anomaly and $E$ the eccentric anomalyeccentric anomaly, how can I show that
$$\frac{dv}{dE}=\frac{b}{r}=\frac{\sin v}{\sin E}$$$$\frac{dv}{dE}=\frac{b}{r}=\frac{\sin v}{\sin E}~?$$
If $v$ is the true anomaly and $E$ the eccentric anomaly, how can I show that
$$\frac{dv}{dE}=\frac{b}{r}=\frac{\sin v}{\sin E}$$
If $v$ is the true anomaly and $E$ the eccentric anomaly, how can I show that
$$\frac{dv}{dE}=\frac{b}{r}=\frac{\sin v}{\sin E}~?$$
