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Apr 13, 2017 at 12:39 history edited CommunityBot
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Jan 2, 2016 at 22:09 vote accept user5539357
Jan 1, 2016 at 21:35 comment added Floris Thanks for picking up where I left off... I couldn't get through somehow.
Jan 1, 2016 at 20:22 comment added Gert @user5539357: from a rotational POV, the normal force provides the centripetal force, while $mg\sin\theta$ provides the decelerating force.
Jan 1, 2016 at 19:52 comment added user5539357 @Gert yes, I'm aware of that in only happens in the bend. What about my answers, do they make any sense?
Jan 1, 2016 at 19:38 comment added Gert Note that vertical upward acceleration only takes place in the bend, that's why it didn't show up in my answer. What happens in the bend can be shown by considering it a rotation but not w/o calculus.
Jan 1, 2016 at 18:32 comment added user5539357 More or less? I mean the 3 questions.
Jan 1, 2016 at 18:17 comment added user5539357 1. The normal force becomes $mg \cos\alpha$ ($\alpha$ is the slope angle). 2. Again, $mg \cos\alpha$. 3. It will increase, just like in the case when the ball was going in the opposite direction, up the slope. Technically, is it caused by the centrifugal force? (centrifugal force appears in non-inertial frame reference, and the frame reference here would be a piece of slope with the ball).
Jan 1, 2016 at 17:39 history answered dmckee --- ex-moderator kitten CC BY-SA 3.0