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Dec 18, 2015 at 18:07 comment added higgsss Differentiating $U(t,s) U(s,t) = I$ with respect to $t$ and then rearranging a little gives you $\partial_{t}U(t,s) = - U(t,s) \partial_{t}U(s,t) U(t,s)$. Substituting this in the first equation of (*), then multiplying both sides by $U(s,t)$ on the left as well as on the right, and finally exchanging the variables $t$ and $s$ show that $H(s) = H(s)^{\ast}$.
Dec 18, 2015 at 17:38 history answered yuggib CC BY-SA 3.0