Timeline for Why doesn't photoelectric current increase with frequency of the incident wave?
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| May 24, 2017 at 0:59 | answer | added | jdphys | timeline score: 6 | |
| Mar 16, 2017 at 20:17 | history | protected | ACuriousMind♦ | ||
| Mar 13, 2017 at 13:21 | answer | added | Daksh Shah | timeline score: 13 | |
| Dec 5, 2015 at 15:12 | comment | added | Daniel Griscom | It's best if you ask that question separately. And, if you agree with @user76386's answer, you should accept it. (And, welcome to StackExchange: hope you find it helpful.) | |
| Dec 5, 2015 at 14:38 | comment | added | rishabh gupta | Okay thank you I think now I understand. I want to ask one more thing that here we are taught that intensity is related to the no. Of photons, is it wrong? Wht is the relation between them. | |
| Dec 5, 2015 at 14:07 | comment | added | Daniel Griscom | You're confusing intensity with quantity. In your scenario, the number of incident photons per time is constant, even though the energy is increasing, right? Then the number of resulting electrons per time is constant. | |
| Dec 5, 2015 at 13:15 | comment | added | rishabh gupta | See current is given by charge flowing per unit time,I.e. I= n (no of electons) × q (charge on electron)÷ time . On increasing intensity n increases so I increases but on increasing frequency time decreases so I should increase | |
| Dec 5, 2015 at 12:50 | comment | added | Daniel Griscom | Increasing the frequency of each photon doesn't increase the number of photons, just as increasing the energy of each electron doesn't increase the number of electrons. | |
| Dec 5, 2015 at 12:49 | history | edited | Daniel Griscom | CC BY-SA 3.0 |
Grammar
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| Dec 5, 2015 at 12:46 | answer | added | user76386 | timeline score: 1 | |
| Dec 5, 2015 at 12:30 | review | First posts | |||
| Dec 5, 2015 at 12:49 | |||||
| Dec 5, 2015 at 12:28 | history | asked | rishabh gupta | CC BY-SA 3.0 |