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Mar 10, 2017 at 9:42 history edited CommunityBot
replaced http://inspirehep.net/ with https://inspirehep.net/
Dec 4, 2015 at 19:01 comment added honeste_vivere @KyleKanos - You might also mention that the $T \propto P/\rho$ relationship is the interior temperature, which reaches its peak(minimum) value at the center(edge) of the blast wave. However, the temperature will drop off as $T \propto U_{sh}^{2} \propto t^{-6/5}$, where $t$ is time and $U_{sh}$ is the shock speed along the outward normal.
Dec 4, 2015 at 18:58 comment added Kyle Kanos @honeste_vivere: I thought the R-H jump conditions wiki page would cover that, but sadly it does an awful job (briefly mentioned, rather than discussed). I'll look around for a better discussion.
Dec 4, 2015 at 18:55 comment added honeste_vivere @KyleKanos - You could also mention that in the strong shock limit the density compression ratio for an ideal gas goes to something like $\rho_{2}/\rho_{1} \sim \left( \gamma + 1 \right)/\left( \gamma - 1 \right)$... though it looks like that is captured in your figure.
Dec 4, 2015 at 16:18 comment added Kyle Kanos I've updated my answer to address more about the parameters inside the blast wave. Naively taking $T=p/\rho$, you should be able to see the structure of the temperature from the plot.
Dec 4, 2015 at 16:16 history edited Kyle Kanos CC BY-SA 3.0
added more details about the hydro simulation & resulting profiles.
Dec 4, 2015 at 15:45 comment added Kyle Kanos You have to use the mentioned hydrodynamic equations to get that.
Dec 4, 2015 at 15:39 comment added Janosh Thanks for the answer but this doesn't address the issue of how to estimate the density within the explosion.
Dec 4, 2015 at 13:39 history answered Kyle Kanos CC BY-SA 3.0