Timeline for What meaning does the slope of the efficiency path on a Mollier diagram have in terms of temperature?
Current License: CC BY-SA 3.0
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Mar 15, 2012 at 20:53 | comment | added | Jason Waldrop | Sorry I was talking about the straight lines which represent the paths taken by the two turbines. I understand your original comments on the isobaric and isothermal lines now. I was talking about the path lines slope. | |
Mar 15, 2012 at 19:46 | comment | added | tpg2114 | I'm just looking at your plot you put in the post. As the lines move right, they also move up which is a positive slope. Also, isn't it isobaric -- the lines in the figure are labeled with a single pressure? Typically the diagrams consist of constant pressure, constant temperature, and constant volume lines. What is your plot showing? | |
Mar 15, 2012 at 16:26 | comment | added | Jason Waldrop | I don't fully follow your comments. Ok on infinite slope. My lines aren't isobaric since I'm reducing the pressure to internally generate the kinetic energy to turn the turbine blades. As you say this will always be done w/ some irreversibility and so net P will have to decrease. Just from the math the slope has to be negative since $\Delta H$ is negative whereas &\Delta S$ is positive. | |
Mar 11, 2012 at 5:06 | history | answered | tpg2114 | CC BY-SA 3.0 |