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TheAs the total work is equivalent to energy variation ofon the system in whichequals the forces act. Becausechange in kinetic energy must be conserved whe have,: $$W_{Friction}+W_{Potential} = \Delta K$$

Taking: $$v_{i}=v_{f}=0$$ we can write

$$W_{Friction}+W_{Potential} = 0$$ $$W_{Friction}+\Delta V = 0$$ $$W_{Friction}-V_{i} + V_{f} = 0$$ $$W_{Friction} + V_{f}= V_{i}$$ $$E_{i} = W_{Friction} + E_{f}$$

##obs:## Work by definition is $$\int \vec{F}.d\vec{s}$$ from this equation one can derive my statement about the work of gravitational force is equal to the potential energy variation and the total work system equals the change in kinetic energy

The work is equivalent to energy variation of the system in which the forces act. Because energy must be conserved whe have, $$W_{Friction}+W_{Potential} = \Delta K$$

Taking: $$v_{i}=v_{f}=0$$ we can write

$$W_{Friction}+W_{Potential} = 0$$ $$W_{Friction}-V_{i} + V_{f} = 0$$ $$W_{Friction} + V_{f}= V_{i}$$ $$E_{i} = W_{Friction} + E_{f}$$

##obs:## Work by definition is $$\int \vec{F}.d\vec{s}$$ from this equation one can derive my statement about the work of gravitational force is equal to the potential energy variation and the total work system equals the change in kinetic energy

As the total work on the system equals the change in kinetic energy: $$W_{Friction}+W_{Potential} = \Delta K$$

Taking: $$v_{i}=v_{f}=0$$ we can write

$$W_{Friction}+W_{Potential} = 0$$ $$W_{Friction}+\Delta V = 0$$ $$W_{Friction}-V_{i} + V_{f} = 0$$ $$W_{Friction} + V_{f}= V_{i}$$ $$E_{i} = W_{Friction} + E_{f}$$

##obs:## Work by definition is $$\int \vec{F}.d\vec{s}$$ from this equation one can derive my statement about the work of gravitational force is equal to the potential energy variation and the total work system equals the change in kinetic energy

Source Link
sena
sena
  • 1
  • 1

The work is equivalent to energy variation of the system in which the forces act. Because energy must be conserved whe have, $$W_{Friction}+W_{Potential} = \Delta K$$

Taking: $$v_{i}=v_{f}=0$$ we can write

$$W_{Friction}+W_{Potential} = 0$$ $$W_{Friction}-V_{i} + V_{f} = 0$$ $$W_{Friction} + V_{f}= V_{i}$$ $$E_{i} = W_{Friction} + E_{f}$$

##obs:## Work by definition is $$\int \vec{F}.d\vec{s}$$ from this equation one can derive my statement about the work of gravitational force is equal to the potential energy variation and the total work system equals the change in kinetic energy