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Jan 28, 2016 at 5:42 vote accept syzygy
Oct 29, 2015 at 3:50 comment added dmckee --- ex-moderator kitten This is the correct answer, but perhaps you should say that it requires that the open circuit had been left in that state for a sufficiently long time (on order of 100 seconds). And the way to analyze it is to treat the switch as a very low capacitance. So while the flow will start immediately it will sag for a while before rising again on a time-scale given by the communication time to the source (i.e. on the order of 100 seconds).
Oct 29, 2015 at 3:43 history answered Timaeus CC BY-SA 3.0