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Oct 22, 2015 at 15:38 comment added Andrew @WeatherReport Hm I'm not sure I agree with that, if the actions are the same before and after the transformation then the EOMs derived from those actions will be the same too. A subtlety that may or may not be relevant is that when you have linearly realized symmetries involving multiple fields (such as an internal $SO(2)$ symmetry), the EOMs are technically covariant, not invariant, under the transformation.
Oct 22, 2015 at 14:48 comment added Steven Mathey @WeatherReport Could you check this with my example? I expect that KPZ equation is invariant under the non-linear symmetry, but I never checked.
Oct 22, 2015 at 13:59 comment added Weather Report It seems to me, that invariance of Lagrangian is equivalent to invariance of EOM only if this condition ('linearity' as stated in the appendix to the OP) is satisfied. I wish to check this at some particular examples. Maybe I'll make up a separate question on this.
Oct 22, 2015 at 13:18 comment added Andrew What application do you have in mind, out of curiosity?
Oct 22, 2015 at 13:08 comment added Weather Report An interesting example, however not the one I had I mind. Depends on the conventions of course, but I would call this one linear inhomogeneous or something like that. Does not really suit for an application I've been thinking on.
Oct 22, 2015 at 12:53 history answered Andrew CC BY-SA 3.0