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Manishearth
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a=µg$$a=\mu g$$

u=86.4 km/hr$u=86.4 \:\mathrm{km/hr}$

at stoppage,

v=0$$v=0$$

we know that

v^2-u^2=2as$$v^2-u^2=2as$$

0-(86.486.4)=-20.10310distance$$0-(86.4*86.4)=-2*0.103*10*\text{distance}$$

7464.96/2.06=distance$$7464.96/2.06=\text{distance}$$

3623.76km=distance$$3623.76\:\mathrm{km}=\text{distance}$$

a=µg

u=86.4 km/hr

at stoppage,

v=0

we know that

v^2-u^2=2as

0-(86.486.4)=-20.10310distance

7464.96/2.06=distance

3623.76km=distance

$$a=\mu g$$

$u=86.4 \:\mathrm{km/hr}$

at stoppage,

$$v=0$$

we know that

$$v^2-u^2=2as$$

$$0-(86.4*86.4)=-2*0.103*10*\text{distance}$$

$$7464.96/2.06=\text{distance}$$

$$3623.76\:\mathrm{km}=\text{distance}$$

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a=µg

u=86.4 km/hr

at stoppage,

v=0

we know that

v^2-u^2=2as

0-(86.486.4)=-20.10310distance

7464.96/2.06=distance

3623.76km=distance