Timeline for Why is the Spin of the photon neglected?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Oct 6, 2015 at 15:38 | comment | added | rob♦ | Note that if you define $\vec J_\text{photon} = \vec L_\text{photon} + \vec S_\text{photon}$ it's still possible to have $J,L,S=1,1,1$. | |
| Oct 6, 2015 at 15:37 | comment | added | rob♦ | Photon helicity (that is, spin) is at the heart of the Goldhaber et al. neutrino helicity measurement: $E1$ photons from polarized nuclei are circularly polarized. The spin argument in that paper is quite clear. | |
| Oct 6, 2015 at 8:38 | comment | added | SRS | @ rob- But it is also used to determine whether the photon is dipole type or quadrupole type etc using $2^L$, where $L$ is usually associated with $Y_{lm}$. | |
| Oct 5, 2015 at 19:04 | comment | added | rob♦ | I believe $\vec L$ includes both spin and orbital angular momentum, which can't easily be decoupled for the photon. Photon spin is accounted for by the selection rule which says there is no transition matrix element for "monopole" ($L=0$) electronic transitions which preserve nuclear spin, only for dipole transitions and higher. | |
| Oct 5, 2015 at 18:55 | answer | added | anna v | timeline score: 0 | |
| Oct 5, 2015 at 17:52 | answer | added | Name YYY | timeline score: 1 | |
| Oct 4, 2015 at 13:10 | history | tweeted | twitter.com/StackPhysics/status/650659333445951488 | ||
| Oct 3, 2015 at 20:42 | history | asked | SRS | CC BY-SA 3.0 |