Timeline for Can quaternion math be used to model spacetime?
Current License: CC BY-SA 3.0
11 events
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| Sep 28, 2015 at 9:26 | comment | added | Edgar Mueller | I apologize for an error in my last statement. The "delta" operator in quaternion space is, of course, (d^2/dx0^2 - d^2/dx1^2 - d^2/dx2^2 - d^2/dx3^2), i.e. without comas. It is the inner product (dot product) with itself of the quaternionic "nabla" operator, (d/dx0, d/dix1, d/djx2, d/dkx3) = (d/dx0, -id/dx1, -jd/dx2, -kd/dx3). | |
| Sep 25, 2015 at 10:22 | comment | added | Edgar Mueller | The differential operator of Poisson's equation in quaternion space, "delta" = (d/dx0, id/dx1, jd/dx2, kd/dx3)^2 = (d^2/dx0^2, -d^2/dx1^2, -d^2/dx2^2, -d^2/dx3^2), is a wave function operator. | |
| Sep 25, 2015 at 9:56 | comment | added | Edgar Mueller | After transformation to quaternions they become: z0 = x0y0 + x1y1 + x2y2 + x3y3; z1 = x0y1 + x1y0 + x2y3 - x3y2; z2 = x0y2 + x2y0 - x1y3 + x3y1; z3 = x0y3 + x3y0 + x1y2 -x2y1. | |
| Sep 25, 2015 at 9:49 | comment | added | Edgar Mueller | By the way, the algebraic expressions for the "Z" in the 4-squares identity above are bilinear forms as follows: Z0 = X0Y0 - X1Y1 - X2Y2 - X3Y3; Z1 = X0Y1 + X1Y0 + X2Y3 - X3Y2; Z2 = X0Y2 + X2Y0 - X1Y3 + X3Y1; Z3 = X0Y3 + X3Y0 + X1Y2 - X2Y1. | |
| Sep 25, 2015 at 9:39 | comment | added | Edgar Mueller | There is no English translation yet, except the summary. I could make one and post it at an appropriate site, if there is interest; appropriate site suggestions are welcome! | |
| Sep 23, 2015 at 17:00 | comment | added | docscience | Sorry, not following your argument in a nutshell. Is there an English translation of your paper? | |
| S Sep 23, 2015 at 16:09 | history | suggested | SchrodingersCat | CC BY-SA 3.0 |
improved formatting
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| Sep 23, 2015 at 15:43 | review | Suggested edits | |||
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| Sep 23, 2015 at 15:32 | review | Late answers | |||
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| Sep 23, 2015 at 15:16 | review | First posts | |||
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| Sep 23, 2015 at 15:16 | history | answered | Edgar Mueller | CC BY-SA 3.0 |