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Aug 27, 2015 at 18:03 comment added Jim @TMG I don't understand the question. If you define $c$ and $\frac{1}{4\pi\epsilon_0}$ to be 1, the consequence is that $\mu_0=4\pi$ is a necessary constraint.
Aug 27, 2015 at 17:59 comment added TMG What would be the consequences of defining the value of $c$ and $\frac{1}{4\pi\epsilon_0}$ and $\mu_0$ ($=4\pi$ in this system)?
Aug 27, 2015 at 17:56 history answered Jim CC BY-SA 3.0