Timeline for Induction equation in a rotating frame
Current License: CC BY-SA 4.0
17 events
| when toggle format | what | by | license | comment | |
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| May 24, 2022 at 8:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jan 24, 2022 at 3:04 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Sep 18, 2021 at 1:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| May 16, 2021 at 11:04 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jan 16, 2021 at 6:04 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Sep 7, 2020 at 0:06 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| May 7, 2020 at 13:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jan 2, 2020 at 0:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| S Nov 21, 2019 at 6:58 | history | suggested | Cinaed Simson | CC BY-SA 4.0 |
replaced "x" with \times, and "." with \cdot.
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| Nov 21, 2019 at 2:02 | review | Suggested edits | |||
| S Nov 21, 2019 at 6:58 | |||||
| Nov 20, 2019 at 22:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jul 22, 2019 at 14:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Aug 18, 2015 at 18:28 | answer | added | Kewin | timeline score: 1 | |
| Aug 18, 2015 at 15:32 | comment | added | Kewin | I have been using the identity: $\nabla$x(($\Omega$x$r$)x$B$)=($\Omega$x$r$)($\nabla$.$B$) -$B$($\nabla$.($\Omega$x$r$)) + ($B$.$\nabla$)($\Omega$x$r$)-($\Omega$x$r$.$\nabla$)($B$). The two first terms are zero using $\nabla$.$B$=0, $\nabla$x$r$=0 and $\nabla$x$\Omega$=0 (constant rotation). So I am left with ($B$.$\nabla$)($\Omega$x$r$)-(($\Omega$x$r$).$\nabla$)($B$). | |
| Aug 18, 2015 at 0:09 | history | edited | Kewin |
edited tags
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| Aug 17, 2015 at 1:24 | review | First posts | |||
| Aug 17, 2015 at 1:43 | |||||
| Aug 17, 2015 at 1:15 | history | asked | Kewin | CC BY-SA 3.0 |