Timeline for How does the dissolution of salt affect the solution density?
Current License: CC BY-SA 3.0
15 events
| when toggle format | what | by | license | comment | |
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| Nov 16, 2018 at 3:03 | history | protected | AccidentalFourierTransform | ||
| Nov 16, 2018 at 2:20 | answer | added | Emily | timeline score: 0 | |
| Jun 28, 2016 at 11:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| May 23, 2016 at 1:37 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Aug 10, 2015 at 18:49 | answer | added | David White | timeline score: 1 | |
| Aug 10, 2015 at 18:37 | answer | added | gleedadswell | timeline score: 0 | |
| Aug 10, 2015 at 16:32 | answer | added | Joce | timeline score: 0 | |
| Aug 7, 2015 at 21:40 | comment | added | sonicboom | Yes the density of the solution is dependent on temperature (and pressure). That is why I specified we are dealing with an isothermal system. And that page gives no explanation of the constant values it's using for A and B in those functions..it looks like some kind of Taylor expansion... | |
| Aug 7, 2015 at 21:35 | comment | added | csss | ...........nevermind | |
| Aug 7, 2015 at 16:14 | comment | added | John Rennie | Look at the rhocalc() and rhoscalc() functions in the page I linked. The density of saline is not just the composition averaged density of water and solid salt. | |
| Aug 7, 2015 at 15:02 | comment | added | sonicboom | That page talks about ocean water being more dense than "normal" water....Ocean water is water with salt dissolved into it. The ocean water is the solution of two substances, water and salt...so it's density increases according to that page..but I don't think the density of the water "substance" increases...or does it? That's what I'm getting at with my questions. | |
| Aug 7, 2015 at 14:59 | comment | added | sonicboom | I have googled for ages, I have not found anything addressing my specific questions. | |
| Aug 7, 2015 at 14:41 | comment | added | John Rennie | See this web page. Since the calculation is done in Javascript you can see the code doing it. Googling will find you lots more info. | |
| Aug 7, 2015 at 14:21 | review | Suggested edits | |||
| Aug 7, 2015 at 14:35 | |||||
| Aug 7, 2015 at 12:48 | history | asked | sonicboom | CC BY-SA 3.0 |