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Jul 27, 2015 at 14:54 comment added jac As it is a frictionless peg, the string can move without exerting any force on the peg (comparable to a rope over a pulley and a bucket of water attached to one side of the rope and the other rope end loose). So, I cannot imagine how you can have the string in equilibrium unless T1 = T2 in magnitude (not direction).
Jul 27, 2015 at 14:45 comment added Si Chen I'm not sure I understand your response. The string is in mechanical equilibrium. Thus all forces acting on it must balance. If T_1 and T_2 act in the same direction, the only way to balance this, surely, is to have the net reaction force exerted by the peg on the segment wrapped around it be equal to T_1 + T_2, but in the opposite direction?
Jul 27, 2015 at 14:36 history edited jac CC BY-SA 3.0
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Jul 27, 2015 at 14:30 history answered jac CC BY-SA 3.0