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Aug 19, 2021 at 20:22 history edited Qmechanic CC BY-SA 4.0
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Mar 12, 2021 at 17:42 answer added AlmostClueless timeline score: 0
Jul 10, 2015 at 5:09 comment added ZachMcDargh Your derivatives are wrong: $\dot{x} = \dot{r} \cos \alpha$, similarly for $z$. The Euler-Lagrange equation is the equation of motion, and solving it means solving that differential equation.
Jul 9, 2015 at 22:49 comment added Alexander I would guess the constraint is $ z-x\tan(\alpha)=0$, otherwise the motion is not constrained to the surface of the slope.
Jul 9, 2015 at 21:38 history edited ACuriousMind
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Jul 9, 2015 at 21:37 history asked user85159 CC BY-SA 3.0