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Jun 26, 2015 at 19:15 vote accept Caneholder123
Jun 26, 2015 at 16:47 comment added Zo the Relativist @Caneholder123: yes. You're taking the derivative with respect to one configuration variable,w tih the other five held constant.
Jun 26, 2015 at 15:54 comment added Caneholder123 I'm familiar with the notion of phase space, but that's as far as it goes. If the phase space in classical mechanics is consisted of positions and momenta of all particles, would this derivative than be in respect to three-dimensional subspace $(x_\mu, y_\mu, z_\mu)$ of this phase space?
Jun 26, 2015 at 15:34 comment added Caneholder123 So if there are no constraints, it would be same as the whole space?
Jun 26, 2015 at 15:00 history answered Zo the Relativist CC BY-SA 3.0