Timeline for What role does "spontaneous symmetry breaking" play in the "Higgs Mechanism"?
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| Apr 17, 2023 at 14:37 | comment | added | cx1114 | why isn't the global U(1) still a gauge group tho? It does not transform one groundstate to another right ? | |
| Jan 22, 2021 at 7:53 | history | edited | Nihar Karve | CC BY-SA 4.0 |
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| Jan 10, 2019 at 14:35 | comment | added | Nanashi No Gombe | @buzhidao Since we are reinterpreting the original $U(1)$ gauge transformation as a shift in the goldstone (in order to argue that gauge symmetry is intact), and since the new Lagrangian is still invariant under a global shift, does that not mean that the global $U(1)$ phase rotation symmetry is as much intact as the local gauge symmetry? In other words, why do we reinterpret the $U(1) $gauge transformation as a shift of the goldstone, but do not reinterpret the global $U(1)$ symmetry as a global shift invariance? | |
| Aug 11, 2017 at 13:43 | comment | added | an offer can't refuse | @SRS You can ignore that part, I just want to confirm the Lagrangian is gauge invariant. | |
| Aug 7, 2017 at 16:21 | comment | added | SRS | @buzhidao Can you please explain the expression above the statement "Which means the Lagrangian is still gauge invariant." Is it some typo? | |
| Apr 13, 2017 at 12:39 | history | edited | CommunityBot |
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| Mar 12, 2017 at 8:34 | comment | added | an offer can't refuse | @RubenVerresen Because it is easy to check the symmetry operation $\phi\to\phi e^{i c}$ doesn't change the Lagrangian, where $c$ is independent of $x$. | |
| Dec 30, 2016 at 22:14 | comment | added | Ruben Verresen | Great post. I do not see why you call the global U(1) a symmetry though. It is as much gauge as the local part. | |
| Jul 7, 2015 at 13:34 | history | edited | an offer can't refuse | CC BY-SA 3.0 |
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| Jun 22, 2015 at 7:32 | history | answered | an offer can't refuse | CC BY-SA 3.0 |