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Nov 20, 2015 at 11:57 comment added jarm It seems to me that there is a minus sign mistake, as you have $it(\epsilon - \omega -H)$ in the exponential, and then this becomes $\omega + \epsilon - H$ in the delta function.
S Jul 11, 2015 at 14:48 history suggested Minethlos CC BY-SA 3.0
corrected some typos
Jul 11, 2015 at 14:13 review Suggested edits
S Jul 11, 2015 at 14:48
Jun 9, 2015 at 17:13 vote accept Minethlos
Jun 9, 2015 at 16:02 comment added dolun See edit $\uparrow$ for more precision.
Jun 9, 2015 at 16:01 history edited dolun CC BY-SA 3.0
+precisions
Jun 9, 2015 at 14:40 comment added Minethlos Thank you for the thorough answer. I understood everything except the second formula. Can you explain why this $\Psi$ is truly a solution of the Schrödinger equation?
Jun 9, 2015 at 10:09 history answered dolun CC BY-SA 3.0