Timeline for What is the physical reason that the undamped driven oscillator has mean power zero?
Current License: CC BY-SA 3.0
17 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 10, 2015 at 16:33 | comment | added | user36790 | That's so kind. But unfortunately, in India, apart from the Hon'rable PM's residence, we have net speed hardly beyond 60kbps. I went to the link, but it never appeared. Can you imagine this great speed! Now, it is "32 kbps", oh it decreased to 16 .... :( | |
| Jun 10, 2015 at 15:58 | comment | added | ProfRob | @user36790 Read the link I posted above. The solution at resonance is different. | |
| Jun 10, 2015 at 15:29 | comment | added | user36790 | If you take limit, then as $\omega \to \omega_o$, the amplitude tends to be maximum, hmmm....i'm still learning sir; I'm not an expert. | |
| Jun 10, 2015 at 15:00 | comment | added | ProfRob | @user36790 Surely you understand that a stretched spring has potential energy that can be converted back into kinetic energy? | |
| Jun 10, 2015 at 14:58 | comment | added | ProfRob | The solution for $P$ you wrote in your question is NOT true if $\omega = \omega_0$. | |
| Jun 10, 2015 at 14:09 | vote | accept | CommunityBot | moved from User.Id=36790 by developer User.Id=2911 | |
| Jun 10, 2015 at 14:07 | comment | added | user36790 | And if the net power is zero, how can an undamped oscillator has resonance?? I've asked you so many, so extremely sorry for bothering. But if you help me realise these things, I'll be gateful. | |
| Jun 10, 2015 at 14:01 | comment | added | user36790 | I could by now understand that to maintain steady-state, the net work done by the force should be zero. Thus the net power is zero. But, sir, can you tell what actually happens to the oscillator that it returns the work after a quarter cycle? Just a qualitative explanation like your other answer:) | |
| Jun 9, 2015 at 10:45 | comment | added | ProfRob | The first line of your question is "The instantaneous power absorbed by an undamped driven oscillator". UNDAMPED. | |
| Jun 9, 2015 at 10:11 | comment | added | ProfRob | @user36790 Your question does not make any sense. If the oscillator is undamped and you remove the driving force, what will happen? I assume that the solution for the power you wrote above is the steady-state solution, so the amplitude is not changing with time. The transient solution looks different and has a sinusoidal term at the natural frequency too. The solution you wrote down is also not true for resonance. see maplesoft.com/content/EngineeringFundamentals/7/MapleDocument_7/… | |
| Jun 9, 2015 at 9:48 | comment | added | user36790 | So, what is actually the function of driving force if it is not imparting any energy? And what is actually happening at resonance at which the oscillator responses most? If it doesn't get any energy, then how does the amplitude increase? | |
| Jun 7, 2015 at 18:57 | comment | added | ProfRob | @user36790 It doesn't impart any energy. That's why the average power expended is zero. | |
| Jun 7, 2015 at 13:39 | comment | added | user36790 | So, where does the energy that the driving force imparts go? | |
| Jun 7, 2015 at 12:53 | history | edited | user36790 | CC BY-SA 3.0 |
hmm... removed few typos & rectified grammatical mistakes:\
|
| Jun 7, 2015 at 9:21 | history | edited | ProfRob | CC BY-SA 3.0 |
added picture
|
| Jun 7, 2015 at 9:13 | history | edited | ProfRob | CC BY-SA 3.0 |
added picture
|
| Jun 7, 2015 at 8:44 | history | answered | ProfRob | CC BY-SA 3.0 |