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Jun 5, 2015 at 19:29 history edited rob CC BY-SA 3.0
units in upright font
Jun 5, 2015 at 19:28 comment added rob Do you mean to have the $\pi^-$ with negative mass in your question? Rest masses are always positive.
Jun 5, 2015 at 11:05 comment added Physkid @Omry Thank you. Helps to get subtleties and conventions out of the way.
Jun 5, 2015 at 11:02 comment added Omry No, in the standard model, all masses are positive.
Jun 5, 2015 at 10:59 comment added Physkid @JohnRennie This makes sense. Good time to recall concepts on SR. Also, for an particle A with rest mass, M, do we perform a negation on the rest mass such that the rest mass for the antiparticle of A has rest mass, -M?
Jun 5, 2015 at 10:44 comment added Omry Rest mass isn't conserved, best example I can think of this is $H\rightarrow \gamma\gamma$
Jun 5, 2015 at 10:38 comment added John Rennie @Physkid: in quantum field theory mass can change into (kinetic) energy and vice versa. That's how two 1GeV protons can produce a 125GeV Higgs boson in the LHC. In this case mass is being converted into kinetic energy. If you add up the total energy given by $E^2 = p^2c^2 + m^2c^4$ before and after you'll find it is constant.
Jun 5, 2015 at 10:37 review Close votes
Jun 5, 2015 at 19:29
Jun 5, 2015 at 10:16 comment added innisfree Hello, your question is perfectly sensible, but I think it's been asked and answered here before. I suggest you read the above the question and answers. For that reason, I'm suggesting that this question is closed.
Jun 5, 2015 at 10:15 comment added innisfree possible duplicate of Is (rest) mass conserved in special relativity?
Jun 5, 2015 at 10:14 comment added Physkid @JohnRennie John, could you elaborate?
Jun 5, 2015 at 10:10 comment added John Rennie The mass deficit goes into the kinetic energy of the decay products
Jun 5, 2015 at 10:07 history asked Physkid CC BY-SA 3.0