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Edward Hughes
Edward Hughes
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This is the question:

A ball is projected horizontally with a speed "v"$v$ from the top of a plane inclined at an angle of 45 degrees with the horizontal. How far from the point of projection will the ball strike the plane?

My attempt at a solution:

I used the range formula for an inclined plane and I got the answer as (sqrt)2 v^2/g$\sqrt{2} v^2/g$, which somehow isn't the right answer. Any suggestions?

This is the question:

A ball is projected horizontally with a speed "v" from the top of a plane inclined at an angle of 45 degrees with the horizontal. How far from the point of projection will the ball strike the plane?

My attempt at a solution:

I used the range formula for an inclined plane and I got the answer as (sqrt)2 v^2/g, which somehow isn't the right answer. Any suggestions?

A ball is projected horizontally with a speed $v$ from the top of a plane inclined at an angle of 45 degrees with the horizontal. How far from the point of projection will the ball strike the plane?

My attempt at a solution:

I used the range formula for an inclined plane and I got the answer as $\sqrt{2} v^2/g$, which isn't the right answer. Any suggestions?

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EuclidAteMyBreakfast
EuclidAteMyBreakfast
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Horizontal Projection From The Top Of An Inclined Plane

This is the question:

A ball is projected horizontally with a speed "v" from the top of a plane inclined at an angle of 45 degrees with the horizontal. How far from the point of projection will the ball strike the plane?

My attempt at a solution:

I used the range formula for an inclined plane and I got the answer as (sqrt)2 v^2/g, which somehow isn't the right answer. Any suggestions?