Timeline for Physical reason behind having greater amplitude when driving frequency$ < $ natural frequency than that when driving frequency $>$ natural frequency
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| May 27, 2015 at 8:05 | comment | added | John Rennie | Yes. Even with a slow driving frequency there will be short periods at the turnaround points in the oscillation where the force acts opposite to the direction of motion. | |
| May 27, 2015 at 8:02 | comment | added | user36790 | And I suppose it is right(rather than pedantic) to mention "most of the time" because at occasional times the phase can be different, right? | |
| May 27, 2015 at 7:42 | comment | added | user36790 | Thanks a lot for your response. Already said that Name is correct, but even Mr. French also deduced the formula from which it can be easily comprehensible. What I wanted is what really is going physically & that you've explained greatly. Henceforth, I accepted your ans. Thanks again for the prompt reply & sorry if I've vexed you:) | |
| May 27, 2015 at 7:35 | vote | accept | CommunityBot | moved from User.Id=36790 by developer User.Id=2911 | |
| May 27, 2015 at 6:47 | history | answered | John Rennie | CC BY-SA 3.0 |