Two electrons can move in a double helix at very high speeds. $$ F_{electrostatic repulsion } = \frac{ke^2}{r^2}$$ But on the other hand we also have $$ F_{magnetic attraction} = \frac{μ_0 . e^2 v^2}{4 \pi . r^2}$$ So my conclusion is that as the two electrons move in a double helix there must be an attractive force to give the centripetal acceleration to stay in this motion.
As you can see from the formulae for attraction there must be a velocity.

Two electrons when they move experience these forces $$ F_{electrostatic repulsion } = \frac{ke^2}{r^2}$$ And, $$ F_{magnetic attraction} = \frac{μ_0 . e^2 v^2}{4 \pi . r^2}$$

As you can see from the formulae for attraction there must be a velocity.
For the two forces to be the same the speed of the electrons must as fast as light, practically these two electrons will move in a double helix with increasing radius.