Timeline for How to get the pressure amplitude at any spatial point?
Current License: CC BY-SA 3.0
4 events
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| Jun 9, 2017 at 19:57 | comment | added | nasu | There is no "R" in the original article. The position is determined by the variable "r" both in the amplitude and in the phase terms. The amplitude simply decreases as 1/r and does not depend on time. There is no angular dependence as the source emits equally in all directions (see text of article). | |
| May 18, 2015 at 6:05 | comment | added | Victor Pira | Well, it makes sense, because $p(r,\theta,0) = 0$ everywhere except $r=0$ (if you assume a point source located at the origin). That's actually given by initial conditions - you need to state what's going on in $t,r = 0$. The equation then shows a development since then. Nice discussion of these phenomena is in the first parts of Howe's theory of vortex sound | |
| May 18, 2015 at 4:56 | comment | added | Amzocks | Thanks a lot ! Indeed it should be rather simple but what you say implies that at $t=0, p(r,\theta,0) > 0$. Which makes me wonder about the causality of the wave propagation. Isn't it weird ? | |
| May 17, 2015 at 17:52 | history | answered | Victor Pira | CC BY-SA 3.0 |