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Timeline for Can bosons have anti-particles?

Current License: CC BY-SA 4.0

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S Oct 15, 2023 at 21:15 history bounty ended Nightrider
S Oct 15, 2023 at 21:15 history notice removed Nightrider
Oct 10, 2023 at 8:39 answer added OON timeline score: 7
S Oct 9, 2023 at 19:40 history bounty started Nightrider
S Oct 9, 2023 at 19:40 history notice added Nightrider Authoritative reference needed
Jun 20, 2023 at 17:17 comment added R. Romero I've heard Neil Degrasse-Tyson argue that Bosons have no anti-particles. Then I thought of $W^{\pm}$ bosons as well as mesons and their anti-particles. A friend suggested even if charge switches signs and mass is preserved, if they don't annihilate then they aren't anti-particles. I didn't know whether $W^{\pm}$ can annihilate each other so maybe I was in fact mistaken. Now I'm uncertain.
Jan 30, 2019 at 22:47 history edited Qmechanic CC BY-SA 4.0
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Jan 30, 2019 at 21:31 answer added Deschele Schilder timeline score: 1
May 25, 2015 at 16:31 vote accept highsciguy
May 16, 2015 at 20:22 comment added Siva Taylor's point seems to be centered on the following idea "Bosons operate under different laws and can be created singly. This is a crucial distinction and is in nature of being either matter particles or force carriers." (which I simply don't understand)
May 16, 2015 at 20:19 comment added Siva By definition charge conjugation $C$ is that operator which swaps particles and anti-particles. And I have to agree with @innisfree.
May 16, 2015 at 13:59 answer added Paganini timeline score: 5
May 15, 2015 at 19:59 comment added Sebastian Riese I guess Geoff Taylor has a very non-standard viewpoint. Don't let him confuse you.
May 15, 2015 at 19:19 history tweeted twitter.com/#!/StackPhysics/status/599293152101535744
May 15, 2015 at 14:21 comment added innisfree I can't think of any sensible definition of antiparticle under which it's a mistake to say bosons could have antiparticles (you could say anti-particles are only fermions by definition, but why would you say that?!)
May 15, 2015 at 14:17 history edited highsciguy CC BY-SA 3.0
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May 15, 2015 at 14:14 comment added highsciguy For me, it is the C/CP-conjugate of the corresponding particle state. Of course, C and CP are not exact symmetries of the Standard Model but, if this is an issue, I would set the corresponding CP-violating phases to zero for that matter. Which other definition would be sensible?
May 15, 2015 at 14:11 history edited innisfree CC BY-SA 3.0
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May 15, 2015 at 14:09 comment added ACuriousMind Well, this crucially depends on your definition of anti-particle.
May 15, 2015 at 13:49 history asked highsciguy CC BY-SA 3.0