Timeline for Why does Srednicki insist on $\phi$ having zero VEV?
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| May 8, 2015 at 13:01 | comment | added | Javier | But that's not the on-shell-forcing delta function, which would be $\delta(k^2+m^2)$ (in $-+++$ signature). This is just a four dimensional delta function, which forces $k$ to be the zero four-vector. | |
| May 8, 2015 at 12:18 | comment | added | Neuneck | A scalar field does not transform under Lorentz transformations and can therefore have a nonzero expectation value - as experienced in the Higgs mechanism. | |
| May 8, 2015 at 12:14 | history | answered | nickrelativity | CC BY-SA 3.0 |