Terminal velocity of a free falling object is obtained at the moment its acceleration vanishes \begin{equation} \Sigma\mathbf{F}=0. \end{equation} The forces that act on the object while falling are the gravity force, \begin{equation} F_g=-mg, \end{equation} and the drag force \begin{equation} F_d=\frac{1}{2}v_t^2dC_dA \end{equation} where $v_t$ is the terminal velocity, d is the density, $C_d$ is the drag coefficient and A is the cross section of the object. Substituting the expression of the forces into the force equilibrium equation \begin{equation} v_T=\sqrt{\frac{2mg}{d C_dA}}. \end{equation} This solution is written generally for any kind of falling object. For the particular case of a sphere, $A=\pi r^2$ where $r$ is the radius of the sphere. The drag coefficient value, $C_d$, can be found in the literature.

Terminal velocity of a free falling object is obtained at the moment its acceleration vanishes \begin{equation} \Sigma\mathbf{F}=0. \end{equation} The forces that act on the object while falling are the gravity force, \begin{equation} F_g=-mg, \end{equation} and the drag force \begin{equation} F_d=\frac{1}{2}v_t^2dC_dA \end{equation} where $v_t$ is the terminal velocity, d is the density, $C_d$ is the drag coefficient and A is the cross section of the object. Substituting the expression of the forces into the force equilibrium equation we obtain \begin{equation} v_T=\sqrt{\frac{2mg}{d C_dA}}. \end{equation} This solution is written generally for any kind of falling object in inviscid fluid. For the particular case of a sphere, $A=\pi r^2$ where $r$ is the radius of the sphere. The drag coefficient value, $C_d$, can be found in the literature.

Terminal velocity of a free falling object is obtained at the moment it's acceleration vanishes \begin{equation} \Sigma\mathbf{F}=0. \end{equation} The forces that act on the object while falling are the gravity force, \begin{equation} F_g=-mg, \end{equation} and the Drag force \begin{equation} F_d=\frac{1}{2}v_t^2dC_dA \end{equation} Where $v_t$ is the terminal velocity, d is the density, $C_d$ is the drag coefficient and A is the cross section of the object. Substituting the expression of the forces into the force equilibrium equation \begin{equation} v_T=\sqrt{\frac{2mg}{d C_dA}}. \end{equation} This solution is written generally for any kind of falling object. For the particular case of a sphere, $A=\pi r^2$ where $r$ is the radius of the sphere. The Drag coefficient value, $C_d$, can be found in the literature.

Terminal velocity of a free falling object is obtained at the moment its acceleration vanishes \begin{equation} \Sigma\mathbf{F}=0. \end{equation} The forces that act on the object while falling are the gravity force, \begin{equation} F_g=-mg, \end{equation} and the drag force \begin{equation} F_d=\frac{1}{2}v_t^2dC_dA \end{equation} where $v_t$ is the terminal velocity, d is the density, $C_d$ is the drag coefficient and A is the cross section of the object. Substituting the expression of the forces into the force equilibrium equation \begin{equation} v_T=\sqrt{\frac{2mg}{d C_dA}}. \end{equation} This solution is written generally for any kind of falling object. For the particular case of a sphere, $A=\pi r^2$ where $r$ is the radius of the sphere. The drag coefficient value, $C_d$, can be found in the literature.