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Oct 5 at 23:11 comment added benrg "2. Only fermions in the $L$ representation of the Lorentz group couple to the $SU(2)$ gauge field." - this doesn't really make sense. If you look at just the fermions and gauge fields, there's no difference between $SU(2)$ and $SU(3)$. It's only because the Higgs has $SU(2)$ and not $SU(3)$ charge, and we treat Higgs-coupled particle pairs as the "same" particle, that we find $SU(2)$ and not $SU(3)$ couples differently to halves of the "same" particle. It's not because of any property of the gauge fields themselves or of the fermion charges.
S May 6, 2018 at 20:08 history mod moved comments to chat
S May 6, 2018 at 20:08 comment added ACuriousMind Comments are not for extended discussion; this conversation has been moved to chat.
May 7, 2015 at 14:19 history bounty ended CommunityBot
May 4, 2015 at 22:12 history edited Edward Hughes CC BY-SA 3.0
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May 4, 2015 at 20:45 history edited Edward Hughes CC BY-SA 3.0
removed vague statement, added references
Apr 30, 2015 at 12:52 history answered Edward Hughes CC BY-SA 3.0