Timeline for What determines the forward voltage drop for a diode?
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Sep 17, 2018 at 19:45 | answer | added | user16035 | timeline score: 0 | |
| Feb 28, 2018 at 19:30 | answer | added | iwakun | timeline score: -1 | |
| Apr 13, 2017 at 12:40 | history | edited | CommunityBot |
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| Oct 12, 2016 at 6:07 | answer | added | Art Brown | timeline score: 2 | |
| Apr 27, 2015 at 21:07 | answer | added | Jon Custer | timeline score: 4 | |
| Apr 25, 2015 at 18:15 | comment | added | rob♦ | @JonCuster Not much elaboration would be needed; my solid-state background is so weak that your brief comments here have already been very helpful. My library seems to have Sze on the shelf; do you have other recommendations? | |
| Apr 24, 2015 at 22:39 | comment | added | Jon Custer | Well, I was kind of hoping to avoid the elaboration! Even Sze doesn't go into it in great detail per se, probably because the crude estimates for forward voltage drops are not elegant enough for him. Instead one tends to find discussion of it in more applied EE books, and they don't want to go into the gory details like Sze. It kind of sits in an awkward place in textbook space. | |
| Apr 24, 2015 at 21:59 | comment | added | rob♦ | @JonCuster Thanks. It would great if you could elaborate in an answer :-) | |
| Apr 24, 2015 at 17:16 | comment | added | Jon Custer | The threshold, or turn-on, voltage depends, to first order, on a balance between the reverse current (carrier generation) and forward current (carrier capture) occurring in the junction. Thus, it is more involved than just the bandgap, although from SRH theory that would clearly impact both generation and capture. | |
| Apr 23, 2015 at 6:52 | history | edited | Qmechanic♦ |
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| Apr 23, 2015 at 6:39 | history | asked | rob♦ | CC BY-SA 3.0 |