Timeline for Minimum size of black hole
Current License: CC BY-SA 3.0
11 events
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| Jul 30 at 11:42 | comment | added | Felix Tritschler | Well, according to your own answer, the minimum size for naturally occuring black holes (barring hypothetical primordial BHs) is ~25 solar masses minus the expelled mass, essentially yielding the TOV limit (~2.01 to 2.17 solar masses). - Then, one could indeed say there's a minumum density, but w/o further explanation that would imply this is a fixed value, which is not the case. It, itself, depends on the mass (which determines the Schwarzschild radius --> mass / (SSR^3*π*4/3) = upper limit of density, but only if homogeneous). | |
| Apr 15, 2015 at 15:18 | history | edited | Sarah Messer | CC BY-SA 3.0 |
Added links for context
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| Apr 14, 2015 at 22:08 | history | edited | Sarah Messer | CC BY-SA 3.0 |
deleted 71 characters in body
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| Apr 14, 2015 at 22:08 | comment | added | Sarah Messer | I did ignore Hawking radiation, and didn't mean to treat the LHC as a shoot-down-the-Moon gun. I was trying to show that the black-holes one might get from the LHC would not stick around long enough for the Earth to get sucked in. Such was a concern in some quarters before the accelerator's upgrade. I'll remove the lunar sentence. | |
| Apr 13, 2015 at 22:04 | comment | added | ProfRob | This scenario (I mean paragraph 2) sounds quite wrong to me. What about Hawking radiation? To get to the moon, travelling at the speed of light, you would have to create black holes of mass $>10^{5}$ kg, since a lower mass black hole would evaporate in a fraction of a second, releasing $\sim 10^{21}$ J during that time. The black holes you are talking about would evaporate in a vanishingly short time. | |
| Apr 13, 2015 at 21:06 | comment | added | Sarah Messer | Thanks to @kyle-kanos for correcting me. To answer benichiwa's concern: The singularity itself reaches possibly-infinite density, but there's a convention of referring to the size of a black hole based on the radius of the event horizon. The black hole's mass can be divided by that volume to yield the density I intended above. My original answer is probably still fudging things slightly, but if Kyle or another astrophysicist can come up with a more-accurate concise answer, I invite them to do so. | |
| Apr 13, 2015 at 21:00 | history | edited | Sarah Messer | CC BY-SA 3.0 |
Incorporated corrections from commenter Kyle Kanos
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| Apr 10, 2015 at 22:32 | comment | added | Kyle Kanos | Massive stars do not explode due to thermonuclear runaway, that is the low-mass stars. Massive stars go through core-collapse. And you typically need at least 25 solar masses to get a black hole. | |
| Apr 10, 2015 at 22:27 | vote | accept | Benichiwa | ||
| Apr 10, 2015 at 22:27 | comment | added | Benichiwa | I thought the density of the center of all black holes is infinity because a singularity has infinite density and zero volume. | |
| Apr 10, 2015 at 22:22 | history | answered | Sarah Messer | CC BY-SA 3.0 |