Timeline for How can I relate linear and angular motion using a single formula?
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22 events
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| Sep 30, 2018 at 0:46 | comment | added | John Alexiou | Point A is the point the force is going through. | |
| Sep 29, 2018 at 14:29 | comment | added | bobie | The point that has 7/4 ratio $v_A/v_{com}$ is at ca. 3.82 distance from the com, is that what you mean by point A? | |
| Sep 26, 2018 at 15:21 | comment | added | John Alexiou | @bobie - $7/4$ is the ratio of how much more velocity point A has compared to the center of mass due to the rotation of the body. | |
| Sep 26, 2018 at 15:15 | comment | added | bobie | Could you please say in plain English how the value of 7/4 relates to angular motion? | |
| Apr 13, 2017 at 12:39 | history | edited | CommunityBot |
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| May 25, 2015 at 7:51 | comment | added | user77485 | $m' = m_{rod} \frac{I_{rod}}{I_{rod}+m_{rod} r^2}$ => $m' = m \frac{ms^2/12}{ms^2/12+m a^2}$ => $m' = m \frac{s^2/12}{s^2/12+ a^2}$ => $m' = m \frac{s^2}{12a^2 +s^2}$ => $m'/m = \frac{100}{175}=\frac{4}{7} ; m/m'= \frac{12a^2 +s^2} {s^2}=\frac{7}{4} $; here you ignore own precepts, use lengthy derivation, get same simple result, and misinterpret it: $ \dfrac{a+\frac{s^2}{12 a}}{\frac{s^2}{12 a}} = \frac{12a^2+s^2}{12a}* \frac{12 a}{s^2} = \frac{12a^2 +s^2} {s^2}= \frac{175}{100}= m/m' = v_{m'}/v_{cm}=\frac{7}{4} $ | |
| May 25, 2015 at 6:32 | comment | added | user77485 | Whatever op wants (if he knows) this answer is wrong: your equation is just the ratio between m and your m' which relates 2 linear v (quantities?), virtual $v_{m'}$ (which op ignores) and real $v_{cm}$ | |
| May 19, 2015 at 8:49 | vote | accept | Vatsal Manot | ||
| May 18, 2015 at 15:32 | comment | added | John Alexiou | Actually the op doesn't want a ratio of velocities. The op wants a single (fundamental) equation relating linear and angular quantities. | |
| May 18, 2015 at 13:20 | comment | added | John Alexiou | You suppose. I still don't know, velocity at which point? Is the velocity of the force application point important to the op? Is the center of rotation point important to the op. If you have a particular situation you have doubts about you can ask your own question so that others have a chance or respond. Note that you shouldn't ask a "Check my work" question, rather you should ask a "How do I approach this situation/concept". | |
| May 17, 2015 at 22:49 | comment | added | John Alexiou | Are you looking at the same thing exactly? The op question was not clear of what ratio was requested. | |
| S Apr 10, 2015 at 16:57 | history | mod moved comments to chat | |||
| S Apr 10, 2015 at 16:57 | comment | added | David Z | Comments are not for extended discussion; this conversation has been moved to chat. | |
| Apr 8, 2015 at 13:30 | history | edited | John Alexiou | CC BY-SA 3.0 |
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| Apr 8, 2015 at 13:04 | history | edited | John Alexiou | CC BY-SA 3.0 |
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| Apr 5, 2015 at 4:38 | vote | accept | Vatsal Manot | ||
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| Apr 4, 2015 at 21:02 | history | edited | John Alexiou | CC BY-SA 3.0 |
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| Apr 4, 2015 at 20:51 | history | answered | John Alexiou | CC BY-SA 3.0 |