Timeline for One dimensional scattering cross section
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 31, 2015 at 22:07 | comment | added | alanf | A particle can either go through the barrier without bouncing back and forth inside it for a while, or it can be transmitted after bouncing back and forth inside the barrier. The $T$ refers to the amplitude of the latter possibility, the 1 is the amplitude of the former possibility. This division seems arbitrary to me, and possibly to you too, but maybe the author of the document has some reason to make it that eludes me. | |
| Mar 31, 2015 at 15:31 | comment | added | jaromrax | @alanf - $A_{trans}$ is the amplitude.... $T$ a factor seems to have a link to $T$ matrix, that is linked to $S$ matrix $S=I+2iT$, I am trying to dig out something ... thanks for the question | |
| Mar 31, 2015 at 15:30 | comment | added | Watw | Surely $1+T$ is the amplitude it was transmitted? | |
| Mar 31, 2015 at 14:31 | comment | added | alanf | $T$ is the amplitude that the system ended up in $x>a$ by transmission through the barrier. So the probability that it ended up in $x>a$ by transmission through the barrier is $|T|^2$. | |
| Mar 31, 2015 at 13:40 | comment | added | Watw | Yeah, I can't see how to use that here... | |
| Mar 31, 2015 at 13:28 | comment | added | alanf | Do you understand that the probability of a system being in a particular state is a square amplitude of that state? | |
| Mar 31, 2015 at 13:03 | comment | added | Watw | You're saying that it's like this because of definition, but there must be some logic behind the definitions so that $|T|^2$ works out as the correct probability. My problem is I can't see that logic. | |
| Mar 31, 2015 at 12:54 | history | answered | alanf | CC BY-SA 3.0 |