Timeline for Calculating $\langle x | \hat{x} | p \rangle$ in $p$ basis
Current License: CC BY-SA 3.0
16 events
when toggle format | what | by | license | comment | |
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Nov 5, 2015 at 16:20 | answer | added | mike stone | timeline score: 2 | |
Mar 25, 2015 at 5:10 | vote | accept | Frank | ||
Mar 24, 2015 at 15:19 | answer | added | Gonenc | timeline score: 1 | |
Mar 24, 2015 at 14:36 | history | edited | Qmechanic♦ |
edited tags
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Mar 24, 2015 at 4:48 | answer | added | hft | timeline score: 0 | |
Mar 24, 2015 at 2:07 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
Removed the primes which OP has acknowledged as typos
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Mar 24, 2015 at 0:15 | answer | added | Qmechanic♦ | timeline score: 2 | |
Mar 23, 2015 at 22:55 | comment | added | Frank | The one before last step in the first derivation probably cannot be correct, because it is integrating over $p'$, but ignores the $p'$ before $\langle x\ |\ p'\rangle$. | |
Mar 23, 2015 at 22:50 | history | edited | Frank | CC BY-SA 3.0 |
edited title
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Mar 23, 2015 at 22:39 | comment | added | Frank | That is the question! It's wrong in at least one place, and probably several, and I can't seem to figure the wrong step(s) :-) | |
Mar 23, 2015 at 22:38 | comment | added | user73762 | @Frank: You're right, I seem to have forgotten how to integrate and have deleted my unhelpful earlier comment. That leaves an obviously incorrect negative sign to be explained. Just how did you get a different sign for $\langle x|p \rangle$ in the first calculation compared to $\langle x|p^\prime \rangle$ in the second one? | |
Mar 23, 2015 at 21:05 | history | edited | DanielSank | CC BY-SA 3.0 |
TeXified title
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Mar 23, 2015 at 20:41 | history | edited | Frank | CC BY-SA 3.0 |
added 100 characters in body
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Mar 23, 2015 at 20:34 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
edited tags; edited title
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Mar 23, 2015 at 20:33 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
edited tags; edited title
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Mar 23, 2015 at 20:28 | history | asked | Frank | CC BY-SA 3.0 |