Timeline for In photo-electric experiment, if the light is exposed to a metal plate for a long enough interval, does the plate become lighter?
Current License: CC BY-SA 2.5
7 events
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Dec 14, 2010 at 11:06 | vote | accept | Display Name | ||
Dec 8, 2010 at 6:49 | comment | added | Lagerbaer | Yes. That's what I wrote above: "The work to remove the electron becomes higher the more electrons have left". | |
Dec 8, 2010 at 5:43 | comment | added | endolith | Doesn't the energy required to kick off an electron increase as the charge increases? | |
Dec 7, 2010 at 5:35 | comment | added | David Z | Electrons are so light (in the mass sense) that I can't imagine you'd be able to remove enough of them to make a measurable difference in the weight. At least not before the charge on the plate pulls more electrons in to replace the missing ones. | |
Dec 7, 2010 at 5:04 | comment | added | Lagerbaer | You'll need a good vacuum, and a kathode/anode (I always mix these up...) that sucks away all the photo-electrons. And you need light of a high frequency. | |
Dec 7, 2010 at 5:03 | comment | added | Display Name | Interesting explanation. Thank you @Lagerbaer. I don't know whether or not I have a chance to do an experiment like this. It looks so imaginative. :-) | |
Dec 7, 2010 at 4:59 | history | answered | Lagerbaer | CC BY-SA 2.5 |