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Mar 19, 2015 at 21:37 comment added physicist @G.Bergeron I thought boost transformation should transform just like any two indices tensor. I was wrong I think, as ACuriousMind explained.
Mar 19, 2015 at 18:55 comment added G. Bergeron You were right, I talked too fast and supposed wrongly another transformation. Yours does preserve length, but I don't understand why you expect the transformed boost to have the same functionnal form as the boost when expressed relative to the new coordinates: it is not the same transformation.
Mar 19, 2015 at 16:28 vote accept physicist
Mar 18, 2015 at 1:18 history edited physicist CC BY-SA 3.0
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Mar 17, 2015 at 23:26 answer added ACuriousMind timeline score: 5
Mar 17, 2015 at 23:07 comment added physicist @ACuriousMind that's very interesting comment.I was treating a certain Lorentz boost which I can compute, to be a simple tensor of two indices. And so when I transform the coordinates with a certain Jacobean then then the boost matrix should also transform in a similar manner. is my understanding wrong? By the way this is a research question not a homework exercise :)
Mar 17, 2015 at 22:36 comment added user73762 A transformation that changes the metric only in one spatial dimensions seems strange. If you get a length contraction, I (naively) expect there to be some time dillation, too.
Mar 17, 2015 at 22:34 comment added ACuriousMind Why do you think the Lorentz boost "transforms" at all? It is, intrinsically, an element of a group, not a vector or tensor on the space, so why should it transform in any way?
Mar 17, 2015 at 22:32 history edited Qmechanic CC BY-SA 3.0
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Mar 17, 2015 at 22:30 history asked physicist CC BY-SA 3.0