Timeline for Gibbs free energy for an ideal gas (problem)
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Dec 4, 2018 at 14:51 | comment | added | Themis | @ Ronan Tarik Drevon Not quite. If we have an exact differential of the form $dF = A(x,y) dx + B(x,y)dy$ we may integrate it along a path of constant $x$ followed by a path at constant $y$ between any two states. The result then is valid for any path since the differential is exact. | |
| Mar 15, 2015 at 13:45 | comment | added | Ronan Tarik Drevon | I am just saying that when you integrate ∫RlnPdT in RTlnP you are actually assuming P constant which is only true for isobar transformation. Though the expression for the Gibbs energy you are trying to get is a general one so not only for isobar transformation | |
| Mar 12, 2015 at 23:57 | review | Suggested edits | |||
| Mar 13, 2015 at 1:09 | |||||
| Mar 12, 2015 at 23:33 | comment | added | alejandro123 | What? could you explain that again? | |
| Mar 12, 2015 at 23:08 | history | answered | Ronan Tarik Drevon | CC BY-SA 3.0 |