Timeline for Finding the vector potential of an infinite cyclinder with uniform surface current
Current License: CC BY-SA 3.0
3 events
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| Mar 9, 2015 at 13:14 | comment | added | user279043 | I see, so after finding Kb, we can treat this situation as equivalent to one without an insulator but where the bound current is added to the free current. Doing so, I do get the same B I got with M and H. Using Kb = M x n, I got Kb running in the same direction as the free current, and this Kb allowed me to get the correct B. | |
| Mar 9, 2015 at 13:11 | vote | accept | user279043 | ||
| Mar 9, 2015 at 12:39 | history | answered | QuantumEyedea | CC BY-SA 3.0 |