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Mar 6, 2015 at 3:52 answer added Sofia timeline score: 0
Mar 6, 2015 at 3:03 answer added user24081 timeline score: 0
Mar 6, 2015 at 3:01 comment added user24081 Whoops. I just realized I made a very silly error in calculation. Obviously taking $\frac d{dt} y(\tau/2)$ is going to be zero because $y(\tau/2)$ doesn't vary with $t$.
Mar 6, 2015 at 2:59 answer added user36790 timeline score: 2
Mar 6, 2015 at 2:49 history asked user24081 CC BY-SA 3.0