Timeline for $SU(2)$ generators and creation annihilation operators
Current License: CC BY-SA 4.0
12 events
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| Jun 9, 2022 at 20:00 | history | edited | Níckolas Alves | CC BY-SA 4.0 |
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| Aug 14, 2020 at 10:51 | comment | added | Saurabh Shringarpure | What is the difference between real and complex Lie Algebra? | |
| Jun 7, 2015 at 10:44 | vote | accept | Chaos | ||
| Feb 28, 2015 at 20:22 | vote | accept | Chaos | ||
| Jun 7, 2015 at 10:44 | |||||
| Feb 26, 2015 at 19:24 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
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| Feb 26, 2015 at 17:12 | answer | added | Chaos | timeline score: 6 | |
| Feb 26, 2015 at 17:06 | comment | added | Mark Mitchison | You can obviously generate any element of SU(2) by exponentiating a linear combination of $J_z,J\pm$, since this is also a linear combination of $J_z,J_x,J_y$. So in this sense these operators do generate the group, although they are not a conventional choice. | |
| Feb 26, 2015 at 17:01 | comment | added | Phoenix87 | It is the tangent space to the identity of the Lie group (which is also a manifold), i.e. the Lie algebra. | |
| Feb 26, 2015 at 16:53 | comment | added | Chaos | Yes I noticed that. But Georgi says "$J_{\pm}, J_3$ are generators of SU(2) subalgebra" at page 93. I do not know anything about the tangent space of an operator space... | |
| Feb 26, 2015 at 16:52 | history | edited | Chaos | CC BY-SA 3.0 |
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| Feb 26, 2015 at 16:50 | comment | added | lionelbrits | Notice that the ladder operators aren't hermitian, like the generators. However, sometime it is still said that they are elements of the lie algebra, because they are in the same (complexified) tangent space. | |
| Feb 26, 2015 at 16:43 | history | asked | Chaos | CC BY-SA 3.0 |